# N2o4 To 2no2 Pressure

 However, sound propagation is very nearly adiabatic, even at low frequencies. When [A] and [B] are constant, equilibrium is achieved. 2 dissociated it will form 0. 6 Now x × 46 + ( 1-x) 92 = 76. Hence starting with 1 mol asked Nov 18, 2018 in Equilibrium by monuk ( 67. 40 atm NO2(g) at 25°C. 8 atm of the pressure, totaling the 1. When the plunger is rapidly pushed in to decrease the gas volume by half, the color darkens due to. 69 atm The partial pressures of N2O4 and NO2 at equilibrium will be 0. [NO2] was increased. Because H 2 O is the only non-condensed phase present, the equilibrium constant is P(H 2 O) 3 = (. 1 kJ/mol) - 9. The value of. Initial moles of N2O4 was 1, 50% decomposed so. A syringe is filled with a mixture of nitrogen dioxide, NO 2, and dinitrogen tetroxide, N 2 O 4, gases. Solution: The value of Kc for the reaction:N2O4 (g) ⇌ 2NO2 (g)is 0. 050 mole of N2O4 and 0. If we were to put some N2O4 in a flask, the N2O4 molecules would collide with each other and some of them would break apart to form NO2. For this reaction system, it is found that the partial pressure of N2O4 is 3. For equal number of moles of reactants and products, no shift occurs. 14) is reached PLS HELP ME FRNDS!. At this point, the concentrations of all species are constant because these processes are occurring at the same rate. 6 46 x + 92 -92 X = 76. NO 2 is a brown gas, and N 2 O 4 is colorless, so the more NO 2 is present, the darker brown the color of the syringe. $N2O4 <-->2NO2$ pressure initial: $P$ At equilibrium: $P-X +2X$ $0. At some time, the color stops changing and we have a mixture of N2O4 and NO2. 4g of N2O4, and make 6. of each gas when: a. Chemical equilibrium is achieved when: the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products remain constant (requires a closed system) Physical equilibrium H2O (l) Chemical equilibrium N2O4 (g) 14. 360 mole of N2O4 (g) is placed into a 2. When N2O4 is added, the partial pressure of N2O4 increases. if the pressure is increased,the volume have to reduce since both are inversely proportional. 5=P+X [/math. 39 for the reaction below. 62 bar, what is the partial pressure. Thermodynamic properties of the chemically reactive system N2O4 ⇌ 2NO2 ⇌ 2NO + O2 have been evaluated over a pressure range of 0. for the equilibrium N2O4 yields 2NO2 (g), at 298 K, Kp= 0. Since the formation of N2O4 is an exothermic reaction, lowering the temperature shifts the equilibrium in favor of colorless N2O4. Equilibrium Pressure? At a particular temperature, Kp = 0. PNO2 = PN2O4 = 1. Correct answer is option 'A'. Consider the reaction N2O4(g) 2NO2(g) At equilibrium ratefwd = raterev 2 so k[N2O4]eq = k[NO2] eq kfwd [NO2] 2eq then = krev [N2O4]eq. On the microscopic level, only N2O4 molecules are present. For the dissociation reaction N2O4(g) ⇌2NO2(g), the degree of dissociation (α) in terms of Kp and total equilibrium pressure P is:- - 6723501. 8 kJ NO(g) + 1/2 O2(g) NO2(g) Delta Grxn = - for Teachers for Schools for Working Scholars. When NO2(g) is introduced to a flask at 1. At a point during the reaction, [N2O4] = 0. N2O4 is available in various "grades" ranging from pure N2O4 to 25% NO. Lowering the temperature to -5 oC converted the NO2 to N2O4. Kp = Press(NO2)² / Press(N2O4) If the Surroundings (Atm Press) is at 1. What is the equilibrium partial pressure of N2O4? - 488048. Chemical equilibrium is the point at which the concentrations of all species are constant. 400 times the original volume. 55 M and [NO2] = 0. The equilibrium between nitrogen dioxide, NO2, and dinitrogen tetroxide, N2O4, is shown below. 1 Answer to A flask is charged with 1. 43 x 10^-2 atm. and a temperature range of 200° to 900°K. dioxide (NO2) vapor: N2O4 (liquid) H 2NO2 (vapor). When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. Calculate the total pressure in this flask at equilibrium. 9 for the following reaction. 0 atm (this resists the gas produced), then the gas produced must prouce an equal pressure to resist itso if the gas is 0. If the concentrations of both NO2 and N2O4 are 0. Here is an explanation: pressure affects a reversible reaction if the reactants & products are gaseous as in this case. ) As long as the choice had to be made between a low yield of. Adding N2 will increase the total pressure of the system, but N2 is not involved in the reaction. Let's say we have this system in a syringe and we quickly decrease the volume by pushing the. At equilibrium, 25. 40 grams N2O4 to mol = 0. 0821 L*atm/(K*mol) equilibrium. - If you decrease the total pressure on an equilibrium system involving gases, the system will shift in a way that will increase the total pressure. [math] N2O4 <-->2NO2$ pressure initial: $P$ At equilibrium: $P-X +2X$ $0. 00­L flask, what. 32 atm lf the volume is doubled, the pressure becomes half and the reaction proceeds in the forward direction. The vapour pressure of the liquid is well described by the following equation: 1753 log PmmHg = - -'~ + 9. 0821 l-atm/mol-K. 100 atm of N2O4. N2O4(g) 2NO2(g); ∆Ho = +57kJ mol -1? If the temperature of an equilibrium mixture of the gases is increased at constant pressure, will. 28/2 - p)(11/2 + 2p) , where, reactant N2O4 equivalent to pressure P is used up and NO2 equivalent to pressure 2P is formed. 8 atm of the pressure, totaling the 1. [N2O4] was decreased. At low temperature nitrogen dioxide molecules join together to form dinitrogen tetroxide. 00 atm pressure and 25°C. 83 kJ) of reaction can be calculated from the follow standard-state enthalpies of formation and standard-state entropies. If the work done on a system is 5. N2O4/NO2 mixture is measured under conditions of known pressure, temperature, and volume. In order to decide what effect a change in total pressure will have on an equilibrium system with gases, what is the first thing you should do when given the balanced equation?. for the reaction of NO 2 /N 2 O 4 with CF 3 CF 2 CF 2 CH 2 OH at 350 K the rate constants are: k 3 = 5. 00 L container was found to contain 0. c) the reaction is exothermic. 058 mol of N2O4 into a 2. No, there is no law of conservation of moles ! If you use up 1 mol of N2O4, you make 2 moles of NO2. The dissociation of N2O4 was found to be 40% at equilibrium when the reaction is conducted in a 2 litre container at 300 k. N2O4 (g) --> 2NO2 (g) The mixture of N2O4 and NO2 resulting from the reaction occupies 36. 8 atm is allowed to reach equilibrium. In accordance with Le Châtelier’s principle, a shift in the. 6 46 x + 92 -92 X = 76. 00 L vessel contained 0. The melting point is 261. 0-litre flask at 27°C. 00 L container is initially filled with 0. When heated, vapour density decreases to 24. There are 2volumes of NO &1volume of N2O4 HENCE THE REACTION PROCEEDS WITH AN INCREASE IN VOLUME. 100 atm of N2O4. When the volume of the system is decreased at constant temperature, the overall pressure increases; suppose that we were to halve the volume instantaneously. P4O10 + 4HNO3 4HPO3 + 2N2O5. At 298 K, a reaction vessel initially contains 0. Dinitrogen pentoxide, N2O5, is a white solid formed by the dehydration of nitric acid by phosphorus(V) oxide. 2NO2(g) N2O4(g) Asked in Chemistry If the system is at equilibrium what happens if you lower the pressure of the system? 2CO(g) + O2(g) 2CO2(g) CO2 gas is consumed. Kuloor died on February 5, 1970. Calculate the number of moles of NO2 present,if the equilibrium N2O4-----2NO2(KP=0. n is the number of moles of gaseous products minus the number of moles of gaseous reactants. Because P is positive, ΔV must be negative for the work to be positive. The pressure will be only half of what is was with the 2 molecules of NO2: So, to summarize: The greater the number of moles (or molecules) of gas in a particular volume, the. 2 Answers to At a given temperature, the equilibrium constant (Kp) for the decomposition of dinitrogen tetraoxide to nitrogen dioxide is 0. 2NO2 (g) ⇌ N2O4 (g) ΔH = -59. 2NO2(g) [pic] N2O4(g) Kc = 0. 00935 moles). 00 atm NO2(g) at 25 degree C, and the following equilibrium is achieved: N2O4(g) 2NO2 After equilibrium is reached, the partial pressure of NO2 is 0. 14) is reached. At a point during the reaction, [N2O4] = 0. -([N2O4]o - [N2O4]) = [NO2] 5. Worksheet 2-2. 4g of N2O4, and make 6. At some time, the color stops changing and we have a mixture of N2O4 and NO2. What happens to the concentration of N2O4 when the following stress is applied? Does is increase or decrease? Pressure on system decreased Volume of container decreased N2O4 increased Temperature increased Volume of container increased N2O4 removed NO2 increased Pressure on system increased NO2 removed Temperature decreased. after the system reached equilibrium, the total pressure was found to be 7. N2O4 (g) 2NO2 (g) = 4. Calorimetric studies show that the following reaction is exothermic: 2NO2(g) N2O4(g) + 14. 69 - x atm and x atm respectively. The standard enthalpy (delta H = -57. N2O4(g)→2NO2(g) ΔHrxn=55. N2O4 (g) --> 2NO2 (g) The mixture of N2O4 and NO2 resulting from the reaction occupies 36. 8078 x 10-4 T + 2. 1 constant The Haber Process N2(g) + 3 H2(g) 2 NH3(g) Catalyst, pressure of several hundred atm, and several hundred degree Celsius temperature. D) The equilibrium partial pressure of BrCl (g) will be greater than 2. Practice Questions 11. 8/6/2019 Student Copy 14 Lecture Ppt. of reactants equilibrium constant CONSTANT (at a given T) Properties of an Equilibrium Equilibrium systems are • DYNAMIC (in constant motion) • REVERSIBLE • can be approached from either direction Pink to blue Co(H 2O) 6Cl ---> Co(H O) 4Cl. Indicate in which direction. The half-life for the first-order decomposition of is 1. Percentage dissocistion = Therefore, the percentage dissociation is, 61. a catalyst is added. 1 Kp = PNO22/PN2O4 = (1. What is the partial pressure of CO2 in the reaction mixture at this temperature? →Calculate K p →∆n = 1 – 0 = 1 →K p = K c(RT)∆n = 2. Calculate the value of Kp for the reaction. 5 moles N2O4 gives 1 mole NO2. If the total pressure in a flask containing NO2 and N2O4 gas at 25 degree C is1. 2004 Free Response – Form B 1. the reaction that does this is the backward reaction which proceeds with a reduction. The expression for is, Now put all the given values, we get. Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. Nitrogen dioxide equilibrium. a) What is the equilibrium partial pressure of N2O4? 2) At 800 K the equilibrium constant for I2 (g) <===> 2 I(g) is Kc = 3. 0466 mol N2O4 at equilibrium. Understanding and working with equilibrium. The collapsing of the can is due to the greater applied atmospheric pressure compared to the less pressure inside the can. For the reaction, N2O4 2NO2 , if degree of dissociation of N2O4 are 25 The mole fraction of N H 3 as 0. 100 - X 2X Quadratic equation X = 0. 1 Answer to A flask is charged with 1. Increasing the pressure of a gas will increase its concentration. 150] , 300 = [0. 50 grams N2O4 to mol = 0. 5 due to its dissociation to NO2. 00 atm NO2(g) at 25 degree C, and the following equilibrium is achieved: N2O4(g) 2NO2 After equilibrium is reached, the partial pressure of NO2 is 0. 6 46 x = 15. It is a useful reagent in chemical synthesis. How long will it take to decompose 15% of the N2O5?' and find homework help for other. Dinitrogen tetroxide, commonly referred to as nitrogen tetroxide, and sometimes, usually among ex-USSR/Russia rocket engineers, as amyl, is the chemical compound N 2 O 4. 39 for the reaction below. What percentage of N2O4 decomposes at 400K ? Assume that the initial pressure of N2O4 is the same (0. At equilibrium, 25. 01 grams of N2O4 (g) is placed in a container and allowed to dissociate. 25 for the reaction: N2O4 (g) → 2NO2(g). 1 H2O (g) 2NO2 (g) N2O4 (g. Load More Trending Questions. for this reaction system, it is found that the partial pressure 0f N2O4 is 3. 73 mol/L what is the equilibrium concentration of NO2 in mol/L ?. 2NO 2 <=> N 2 O 4 Dynamic Equilibrium New Blender Computer Animation. 50 atm is allowed to reach equilibrium. 38 atm The value of the equilibrium constant will be Kp = P2NO2/PN2O4 = 1. The decomposition of N2O4, in equilibrium mixture of NO2(g) and N2O4(g), can be increased by :a)addition of an inert gas at constant pressure. if the pressure is increased,the volume have to reduce since both are inversely proportional. then find the final pressure. 5 For partial pressure,the total pressure remains the same so you can use the mole ratio to calculate the partial pressure for each gas. At 298 K, a reaction vessel initially contains 0. Calculate the percent dissociation of N2O4 at 46'C at a total pressure of 380 Torr. Lowering the temperature to -5 oC converted the NO2 to N2O4. N2O4 is available in various "grades" ranging from pure N2O4 to 25% NO. Name three essential features of an equilibrium. Let the total number of moles = 1 let the number of moles of NO2 = X so number of moles of N2O4 = 1 -x molar mass of mixture = 2 x vapour density = 2 × 38. The two substances in this reaction are NO2 and N2O4. Determine the vapor pressure of the solution. The half-life for the first-order decomposition of is 1. What is the numerical value of the equilibrium constant? Solution: The vapor pressure is (7. For this reaction system, it is found that the partial pressure of N2O4 is 3. determine the partial pressure of no2 at equilibrium,. When the pressure is decreased, the equilibrium will shift to the side with the higher amount of molecule. At room temperature, it decomposes to brown NO2: N2O4(g) 2NO2(g). Le Chatlier's principle allows us to predict the direction a reaction will take when we perturb the equilibrium by changing the pressure, volume, temperature, or component concentrations. N2O4 goes from. N2O4(g)→2NO2(g) ΔHrxn=55. 2 dissociated it will form 0. 关于气体平衡常数的计算 N2O4 (g) = 2NO2 (g) 浅黄色 深棕色 怎样观察这个反映的平衡是否改变? 如果气压增加会怎样? 这个气体反映的平衡常数是多少?（Kp)单位是什么? 条件是N2O4的分压（partial pressure)是0. Effect of Pressure on Gas-Phase Equilibria Last updated; Save as PDF Page ID 1375; References; Problems; Solutions; Contributors; Le Chatelier's Principle states that a system at equilibrium will adjust to relieve stress when there are changes in the concentration of a reactant or product, the partial pressures of components, the volume of the system, and the temperature of reaction. At a certain temperature, Kp = 27. Nitrogen dioxide equilibrium. N2O4 (g) + heat <-> 2 NO2 (g) At a certain temperature, Kc = 4. Calculate the total pressure in this flask at equilibrium. Initially, what are the pressures of N2O4(g) and NO2(g) at 50 ºC ?. 1 H2O (g) 2NO2 (g) N2O4 (g. 00 atm NO2(g) at 25 °C, and the following equilibrium is achieved: N2O4(g)?2NO2 After equilibrium is reached, the partial pressure of NO2 is 0. 0251 MN2O4, what is the concentration of NO2 at equilibrium?Part 2What is the concentration of N2O4 at equilibrium?. Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g)ΔHorxn=55. Yau Spring 2014**. N2O4 (g) 2NO2 (g) Start with NO2 Start with N2O4 Start with NO2 & N2O4 equilibrium equilibrium equilibrium 14. 38 atm The value of the equilibrium constant will be Kp = P2NO2/PN2O4 = 1. Two oxides of nitrogen are acid anhydrides; that is, they react with water to form nitrogen-containing oxyacids. Calculate (i) Kp and (ii) the percentage dissociation at 0. For equal number of moles of reactants and products, no shift occurs. Apr 27,2020 - 0. 14) is reached PLS HELP ME FRNDS!. 8 kJ At this equilibrium, helium gas was added until the total pressure of twice the original pressure, explain what happens at equilibrium? Diposting oleh. 2 sig figs. 2 P NO2 N2O4(g) 2NO2(g) P N2O4 The Equilibrium Constant Kp P is the partial pressure of that component Kp = L atm 0. 42 atm, respectively. The reaction (as written) isa) always spontaneousb) spontaneous at low temperatures, but not high temperaturesc) spontaneous at high temperatures, but not low temperaturesd) never spontaneouse) cannot tellExplain the choice of your answer. According to this principle system in equilibrium is subjected to a change of temperature, pressure or concentration. N2O4(g) <--> 2NO2(g) A flask containing only N2O4(g) at an initial pressure of 4. Kp = Press(NO2)² / Press(N2O4) If the Surroundings (Atm Press) is at 1. The apparatus is capable of measuring the equilibrium constant and the thermal conductivity of the system simultaneously. N2O4 is a liquid in equilibrium with nitrogen. 2NO2(g)<>N2O4(g); deltaH'=-56. After equilibrium is reached, the partial pressure of NO2 is 0. 1 mole of N2O4 was sealed in a tube under one atmosphere conditions at 25 degree celcius. 25 atm for the reaction below. 360 mol/2 L = 0. with gases • Increasing the pressure favors the side with the fewest particles • Leading to a decrease in pressure • Decreasing the pressure favors the side with the most particles • Leading to an increase in pressure • If particle are equal, pressure has no effect. 29 atm, PN2O4 = 1. Here is an explanation: pressure affects a reversible reaction if the reactants & products are gaseous as in this case. if an ideal gas at 1 atm pressure, is spreading from 20 cm3 to 50 cm3 at constant temp. In both cases the can collapses quickly and dramatically. The equilibrium system can be represented as. NO2 molecules are represented as red, while N2O4 molecules are represented as white. 28/2 - p)(11/2 + 2p) , where, reactant N2O4 equivalent to pressure P is used up and NO2 equivalent to pressure 2P is formed. NO 2 is a brown gas, and N 2 O 4 is colorless, so the more NO 2 is present, the darker brown the color of the syringe. for this reaction system, it is found that the partial pressure 0f N2O4 is 3. If it dissociates to 2NO2 molecules, then when a molecule of N2O4 dissociates, one molecule disappears and two new molecules are formed, so the net is one extra molecule for every molecule of N2O4 that dissociates. Kp = Press(NO2)² / Press(N2O4) If the Surroundings (Atm Press) is at 1. Experiments were carried out using a SITEC high. N2O4 2NO2 0. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. Thermodynamic properties of the chemically reactive system N2O4 ⇌ 2NO2 ⇌ 2NO + O2 have been evaluated over a pressure range of 0. N2O4(g) == 2NO2(g) A certain pressure of N2O4 is initially added to an otherwise evacuated. 5-L vessel at –90°C and let equilibrium be established. Simply stated, the principle says that if an external. 00 atm is allowed to reach equilibrium. Catalysts* Chemical Equilibrium Chapter 17 Equilibrium vs. The dissociation of N2O4 was found to be 40% at equilibrium when the reaction is conducted in a 2 litre container at 300 k. The standard enthalpy (delta H = -57. 0251 MN2O4, what is the concentration of NO2 at equilibrium?Part 2What is the concentration of N2O4 at equilibrium?. Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g)ΔHorxn=55. 753 atm, and N2O4 at a pressure of 0. N2O4 (g) 2NO2 (g) constant N2O4 (g) 2NO2 (g) 2NO2 (g) N2O4 (g) [NO2]2 = 4. Reaction Shift Change; N2O4 (g) + 58. It is a useful reagent in chemical synthesis. 100 - X 2X Quadratic equation X = 0. For the reaction, N2O4 2NO2 , if degree of dissociation of N2O4 are 25 The mole fraction of N H 3 as 0. 2) Changing the Pressure An increase in pressure will shift the equilibrium in the direction that produces the least moles of gas. 2 atm of NO2 gas, and at equilibrium, has a partial pressure of NO2 gas of 0. 4 kJ Le Cha^telier's principle predicts that adding N2 (g) to the system at equilibrium will result in _____. 66 × 10–8 atm. Calculate the equilibrium partial pressure of N2, if the equilibrium partial pressure of O2 = 0. 1 Kp = PNO22/PN2O4 = (1. Consider the following reaction. N2O4 <--> 2NO2. The Kp, for the reaction N2O4 2NO2 is 640 mm at 775K Calculate the percentage dissociation of N2O4 at equilibrium pressure of 160mm At what pressure will the dissociation be 50% - Chemistry - Equilibrium. How long will it take to decompose 15% of the N2O5?' and find homework help for other. 370 for the reaction. 554 bar is introduced into an empty reaction container; after equilibrium is established, the total pressure is 0. With no change in the amount of material in the flask, the volume of the container in question is decreased to 0. at equilibrium, 25. N2O4–> 2NO2 If N2O4 is introduced into an evacuated flask at a pressure of 17. 25 atm for the reaction below. 0 atm of pressure under which the. N2O4 → 2NO2 1 - 0. N2O4(g)→2NO2(g)ΔHorxn=55. An all‐glass apparatus has been used to measure the thermal conductivity of the system N2O4⇌2NO2 by the thick‐wire variant of the hot‐wire method in a temperature range of 32°—90°C and up to a pressure of about 50 cm Hg. NO2/N2O4 Equilibrium Computer Simulation 2NO 2 <=> N 2 O 4 Dynamic Equilibrium New Blender Computer Animation First draft by Jared Brandon, University of Oregon, May, 2018. The half-life for the first-order decomposition of N2O4 is 1. 66=4X^2/P-X$[code ]-1[/code] [math]0. The Le Châtelier principle tells us that in order to maximize the amount of product in the reaction mixture, it should be carried out at high pressure and low temperature. 1 we find the average value of Kc 5 4. Calculate the equilibrium partial pressure of N2, if the equilibrium partial pressure of O2 = 0. Why is the new equilibrium have a higher pressure of $\ce{NO2}$ than the original. 32 atm lf the volume is doubled, the pressure becomes half and the reaction proceeds in the forward direction. Prushan CHM 112 M. 55 M and [NO2] = 0. 7 atm is allowed to reach equilibrium. 310 = 2x^2 / (9-x) and got an x value of 1. PNO2 = PN2O4 = 1. 0 atm of pressure under which the. At 328 K, the Keq for the reaction 2NO2(g) ↔ N2O4(g) is 1. 63 x 10-3 K = [NO2]2 [N2O4] 2NO2 (g) N2O4 (g) K = [N2O4] [NO2]2 ‘ = 1 K = 216 When the equation for a reversible reaction is written in the opposite direction, the equilibrium constant becomes the reciprocal of the original equilibrium constant. N2O4(g)→2NO2(g) ΔHrxn=55. 2 NO2 N2O4 (low temperature) A sample of NO2 sealed inside a glass bulb at 23 oC gave a pressure of 677 Torr. Vapor Pressure: Definition, Equation & Examples Lattice Energy: Definition, Trends & Equation Dalton's Law of Partial Pressures: Calculating Partial & Total Pressures N2O4 arrow 2NO2. 40 atm and 1. If the total pressure in a flask containing NO2 and N2O4 gas at 25 degree C is1. Let's say we have this system in a syringe and we quickly decrease the volume by pushing the. 0mol of CO, 3. (3) The rate of the forward reaction and the rate of the reverse reaction are equal. If the work done on a system is 5. Higher concentration The forward reaction is favored Concept of equilibrium Physical equilibrium Chemical equilibrium Le Châtelier’s principle Effect of temperature Effect of concentration Effect of pressure/ volume more product more reactant Temperature has an effect on the equilibrium N2O4(g) 2NO2(g) Le Châtelier’s principle N2(g) + 3H2. 00 L container is initially filled with 0. 9 kJ ↔ 2NO2 (g) Increasing Pressure: 4HCl (g) + O2 (g) ↔ 2H2O (g) + 2Cl2 (g) Volume is increased: 9. Le-Chatelier's principle elucidate the behaviour of a system at equilibrium, if it is subjected to changes in parameters like pressure, temperature and concentration. 1 constant The Haber Process N2(g) + 3 H2(g) 2 NH3(g) Catalyst, pressure of several hundred atm, and several hundred degree Celsius temperature. Express your answer numerically using two significant figures. from my review. The following equilibrium reaction occurs : N2O4 (g) l 2NO2 (g) ; Kp = 0. 200 mol N2 O4. Calculate the value of Kp for the reaction. Nitrogen dioxide is a chemical compound with the formula NO 2. At a particular temperature, Kp = 0. (a) Calculate the equilibrium concentration of both species in 1. 1atm and 37° C. Kinetics Kinetics: speed of a reaction or process how fast? K vs. 30 grams N2O4 to mol = 0. 2 mmHgmmHg?. What is the partial pressure of CO2 in the reaction mixture at this temperature? →Calculate K p →∆n = 1 - 0 = 1 →K p = K c(RT)∆n = 2. NO2/N2O4 Equilibrium Demonstration Heating or cooling flasks of NO 2 and N 2 O 4 shifts the equilibrium between these two species. What is the partial pressure of CO2 in the reaction mixture at this temperature? →Calculate K p →∆n = 1 – 0 = 1 →K p = K c(RT)∆n = 2.  e Experiments showed that, if 1 mol of N2O4(g) is allowed to come to equilibrium with NO2 under standard conditions, only 20% of the N2O4(g) is converted to. 25 atm for the reaction below. 4 atm is allowed to reach equilibrium. 7Pa,温度是400K. This video the effect of pressure on the NO2 N2O4 equilibrium. This discussion on The value of kp for the equilibrium reaction n2O4 = 2NO2 is 2. (a) Calculate the equilibrium concentration of both species in 1. 1) What is the equilibrium partial pressure of N2O4? 2) What's the value of Kp for the reaction?. Calculate the equilibrium partial pressure of N2, if the equilibrium partial pressure of O2 = 0. 1 H2O (g) 2NO2 (g) N2O4 (g. Chemistry 1011 TOPIC Gaseous Chemical Equilibrium TEXT REFERENCE Masterton and Hurley Chapter 12. 0 kJ/mol of N2O4. 00 atm is allowed to reach equilibrium. In this case, Qc (Qc is p(NO2)/p(N2O4) ) becomes smaller than Kc and therefore equilibrium shifts to the right. The half-life for the first-order decomposition of N2O4 is 1. (a) What is the equilibrium partial pressure of N2O4? atm (b) Calculate the value of Kp for the reaction. A container has a mixture of NO2 gas and N2O4 gas in equilibrium. 6 46 x + 92 -92 X = 76. Determine the value of the equilibrium constant at 25. Consider the following reaction. asked by Neha on August 4, 2011; Chem 2. Dinitrogen tetroxide, commonly referred to as nitrogen tetroxide, and sometimes, usually among ex-USSR/Russia rocket engineers, as amyl, is the chemical compound N 2 O 4. 2 atmand the reactant gas will contribute 0. Le Chatlier's principle allows us to predict the direction a reaction will take when we perturb the equilibrium by changing the pressure, volume, temperature, or component concentrations. The apparatus is capable of measuring the equilibrium constant and the thermal conductivity of the system simultaneously. N 2 O 4 (g) <--> 2 NO 2 (g) ∆ H = 58. NO2/N2O4 Equilibrium Demonstration Heating or cooling flasks of NO 2 and N 2 O 4 shifts the equilibrium between these two species. N2O4(g) 2NO2(g) A flask containing only N2O4(g) at an initial pressure of 3. 000 atm and allowed to come to equilibrium, the equilibrium pressure of N2O4(g) is 0. 50 grams N2O4 to mol = 0. 2 dissociated it will form 0. When the volume of the system is decreased at constant temperature, the overall pressure increases; suppose that we were to halve the volume instantaneously. N2O4 (g) --> 2NO2 (g) The mixture of N2O4 and NO2 resulting from the reaction occupies 36. 28/2 - p)(11/2 + 2p) , where, reactant N2O4 equivalent to pressure P is used up and NO2 equivalent to pressure 2P is formed. 1 Answer to A flask is charged with 1. 1atm and 37° C. 8g N2O4 (g) is introduced into a 1. 00 atm pressure and 25°C. 7 × 10-2 atm at equilibrium. In Table 15. 8 kJ NO(g) + 1/2 O2(g) NO2(g) Delta Grxn = - for Teachers for Schools for Working Scholars. PN2O4 ? atm PNO2 ? atm 2- A flask containing only NO2 at an initial pressure of 9. after the system reached equilibrium, the total pressure was found to be 7. If you want to calculate the change in enthalpy, though, you need to consider two states - initial and final. I did N2(g) + 2 O2(g) -> N2O4(g) I -- 0. 21 at 1000C. 1 constant The Haber Process N2(g) + 3 H2(g) 2 NH3(g) Catalyst, pressure of several hundred atm, and several hundred degree Celsius temperature. What the pressure at which. Answer to: Use the following reactions with known Delta Grxn values: N2O4(g) 2NO2(g) Delta Grxn = 2. addition of a catalyst. If the total pressure in a flask containing NO2 and N2O4 gas at 25 degree C is1. Chemical equilibrium is achieved when: the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products remain constant (requires a closed system) Physical equilibrium H2O (l) Chemical equilibrium N2O4 (g) 14. edu is a platform for academics to share research papers. Sample Problem 17. The value of. -What percentage of N2O4 decomposes at 350 K? Assume that the initial pressure of N2O4 is. When NO2(g) is introduced to a flask at 1. Chemical equilibrium is the point at which the concentrations of all species are constant. 63 3 1023; therefore, K9c 5 0. 1×10-4 atm ¾Use K c (or Q c) if molarities are given , K p (or Q p) if partial pressures are given, or K (or Q) for mixed expressions. How is this problem done? We know: Delta H of reaction = 55. 8Equilibrium 0. -([N2O4]o - [N2O4]) = [NO2] 5. 69 - x atm and x atm respectively. Line up the 3 beakers in a row. 4 kJ + 2HI(g) ↔ H2 (g. I'v tried everything. N2O4(g) --> 2 NO2(g) If a reaction vessel initially contains an N204 concentration of 0. N2O4 (g) --> 2NO2 (g) The mixture of N2O4 and NO2 resulting from the reaction occupies 36. The half-life for the first-order decomposition of is 1. calculate the value of kp for this reaction. Calculate the number of moles of NO2 present,if the equilibrium N2O4-----2NO2(KP=0. Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g)ΔHorxn=55. D) The equilibrium partial pressure of BrCl (g) will be greater than 2. Because H 2 O is the only non-condensed phase present, the equilibrium constant is P(H 2 O) 3 = (. The temperature and pressure dependence of the equilibrium N2O4 ⇌ 2NO2 was studied to investigate these matters. Chapter 14. me and a few others had trouble with this one. Answer to: N2O4 arrow 2NO2 If a 5 L reaction vessel, held at a constant temperature, is initially filled with 10 mol pure N2O4(g), and if 3. 1 Answer to A flask is charged with 1. le Châtelier's Principle: Changing Gas Pressure. The dissociation of dinitrogen tetraoxide into nitrogen dioxide is represented by the equation below. The Concept of Equilibrium CHM 112 M. Chemical equilibrium is achieved when: the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products remain constant (requires a closed system) Physical equilibrium H2O (l) Chemical equilibrium N2O4 (g) 14. Chemical equilibrium partial pressure. For the dissociation reaction N2O4(g) ⇌2NO2(g), the degree of dissociation (α) in terms of Kp and total equilibrium pressure P is:- - 6723501. 9 for the following reaction. 129 mol of N 2 O 4 with chloroform as the solvent. At equilibrium, as much N2O4 reacts to form NO2 as NO2 reacts to re-form N2O4 The double arrow implies the process is dynamic. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. Kp = Press(NO2)² / Press(N2O4) If the Surroundings (Atm Press) is at 1. For the equilibrium N2O4(g) 2NO2(g), at 298 K, Kp = 0. At room temperature, it decomposes to brown NO2: N2O4(g) 2NO2(g). What happens to the concentration of N2O4 when the following stress is applied? Does is increase or decrease? Pressure on system decreased Volume of container decreased N2O4 increased Temperature increased Volume of container increased N2O4 removed NO2 increased Pressure on system increased NO2 removed Temperature decreased. 0116 M NO2 0. system will shift in a way that will reduce the total pressure. From these data we can conclude. One mole of N2O4 (g) at 300K is kept in a closed container under one atmosphere pressure. 400 times the original volume. 2 mmHgmmHg?. The half-life for the first-order decomposition of is 1. For your reaction: $\ce{N2O4 <=> 2NO2}$ {\ce{NO2}}}{P_{\ce{N2O4}}} We know the total pressure, but we do not know the partial pressures of each species. determine the partial pressure of no2 at equilibrium,. Determine the value of the equilibrium constant at 25. after the system reached equilibrium, the total pressure was found to be 7. towards the reactants (since the # moles of reactants is less than the products). 500 atm of N2O4 (g) and 1. When NO2(g) is introduced to a flask at 1. Increasing the pressure will have what effect on the equilibrium? 1. 016 mol L-1, what is - Answered by a verified Tutor We use cookies to give you the best possible experience on our website. At equilibrium N2O4(g)⇌2NO2(g)the observed molecular weight of N2O4is 80g mol−1 at 350 K. 2NO2 -( N2O4 + heat energy. N2O4(g) ↔ 2NO2(g) Since Volume (V) is inversely related to the pressure (P), a decrease in V will cause an increase in P. 0225] Kc = Pressure. 00 atm NO2(g) at 25 °C, and the following equilibrium is achieved: N2O4(g)?2NO2 After equilibrium is reached, the partial pressure of NO2 is 0. * Clicker Question (1/3) Consider the reaction 2NO2(g) N2O4(g). The expression for is, Now put all the given values, we get. CHEMICAL EQUILIBRIUM Chapter 16 a A + b B 'c C + d D K = [C]c [D]d [A]a [B]b conc. Because H 2 O is the only non-condensed phase present, the equilibrium constant is P(H 2 O) 3 = (. 0311 M and [N2O4] = 0. What happens to the concentration of N2O4 when the following stress is applied? Does is increase or decrease? Pressure on system decreased Volume of container decreased N2O4 increased Temperature increased Volume of container increased N2O4 removed NO2 increased Pressure on system increased NO2 removed Temperature decreased. This process is indicated by the. Because P is positive, ΔV must be negative for the work to be positive. Kuloor died on February 5, 1970. NO2 molecules are represented as red, while N2O4 molecules are represented as white. Therefore, the more gas you have, the more increase in concentration. Based on this information, which one—if any—of the following additional changes would increase the molar concentration at equilibrium of N2O4(g)? decrease in pressure increase in temperature decrease in concentration of NO2(g). 0 mmHg , how many seconds are required for the pressure of NO2 to reach 1. Low-boiling (boiling point 21. 75 calculate the partial pressure of each gas in the mixture. Chemical Equilibrium. find the equilibrium constant and the number of reactants and products. Consider the reaction N2O4(g) 2NO2(g) At equilibrium ratefwd = raterev 2 so k[N2O4]eq = k[NO2] eq kfwd [NO2] 2eq then = krev [N2O4]eq. 5=P+X [/math. 100 grams N2O4 to mol = 1. Indian Institute of Science, Bangalore, India. 500 atm of N2O4(g) and 1. At room temperature, it decomposes to brown NO2: N2O4(g) 2NO2(g). 2 Kp = 2 PNO PO 2 PNO 2 2 PO 2 = Kp PNO 2 2 PNO 2 PO 2 = 158 x (0. The standard enthalpy (delta H = -57. c) the reaction is exothermic. A flask is charged with 1. 7 × 10-2 atm at equilibrium. 00 L vessel contained 0. The value of. Hence starting with 1 mol asked Nov 18, 2018 in Equilibrium by monuk ( 67. the reaction that does this is the backward reaction which proceeds with a reduction. Consider the following: N2O4(g) ⇌ 2NO2(g) Colourless Brown. I did N2(g) + 2 O2(g) -> N2O4(g) I -- 0. PN2O4 ? atm PNO2 ? atm 2- A flask containing only NO2 at an initial pressure of 9. N2O4 2NO2 0. From these data we can conclude. For the reaction, Kc = 0. A reinvestigation of the structure of N2O4 in the gas phase at −21oC has given results in good agreement with an earlier study so far as the molecular shape is concerned, but the size of the. oxygen is added. The equilibrium remains unchanged. Chapter 14. 420atm C X 2X -X E x (0. Thermodynamic properties of the chemically reactive system N2O4 ⇌ 2NO2 ⇌ 2NO + O2 have been evaluated over a pressure range of 0. 5 For partial pressure,the total pressure remains the same so you can use the mole ratio to calculate the partial pressure for each gas. ΔH° = 2(H° of NO2) - (H° of N2O4) = 2(33. The effect of temperature on equilibrium - N2O4 to 2NO2. it will favor the reverse reaction, since that's the side that. towards the reactants (since the # moles of reactants is less than the products). Because P is positive, ΔV must be negative for the work to be positive. N2O4 goes from. 28/2 - p)(11/2 + 2p) , where, reactant N2O4 equivalent to pressure P is used up and NO2 equivalent to pressure 2P is formed. Partial Pressure Of No2 N2O4. On the microscopic level, only N2O4 molecules are present. I need some serious help. The equilibrium shifts when the temperature changes inside the vessel. Equilibrium. observed) molecular weight of 69, calculate Kp. Chemistry 12. Thermodynamic properties of the chemically reactive system N2O4 ⇌ 2NO2 ⇌ 2NO + O2 have been evaluated over a pressure range of 0. What percentage of N2O4 decomposes at 400K ? Assume that the initial pressure of N2O4 is the same (0. It is a useful reagent in chemical synthesis. 2 Kp = 2 PNO PO 2 PNO 2 2 PO 2 = Kp PNO 2 2 PNO 2 PO 2 = 158 x (0. When NO2(g) is introduced to a flask at 1. 0225] Kc = Pressure. the reaction that does this is the backward reaction which proceeds with a reduction. 69 atm The partial pressures of N2O4 and NO2 at equilibrium will be 0. Therefore the temperature of the medium. The reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated as a rocket fuel. 100 atm of N2O4. 150] , 300 = [0. The effect of temperature on equilibrium - N2O4 to 2NO2. Equilibrium Between Nitrogen Dioxide and Dinitrogen Tetroxide Materials. 00 atm NO2 (g) at 25 degrees Celsius, and the following equilibrium is achieved: N2O4(g) --> 2NO2(g). 100 atm of N2O4. The total number of molecules in the system will be increased because of that. a) the dissociation grade (noted as $\alpha$) of $\ce{N2O4}$ at equilibrium, in standard conditions. When [A] and [B] are constant, equilibrium is achieved. 50 grams N2O4 to mol = 0. In this case, Qc (Qc is p(NO2)/p(N2O4) ) becomes smaller than Kc and therefore equilibrium shifts to the right. Chemical Equilibrium Chapter 14 Equilibrium is a state in which there are no observable changes as time goes by. -What percentage of N2O4 decomposes at 350 K? Assume that the initial pressure of N2O4 is. Consider the following equilibrium: Now suppose a reaction vessel is filled with 4. For example: In a certain gas mixture containing NO and CO2 gases: Partial Pressure of NO = 40 kPa (kilopascals-a unit of pressure) Partial Pressure of CO2 = 60 kPa Total Pressure = 40 + 60 = 100 kPa If you add some NO, it's partial pressure will go up. 5 Comparing Q and K to Determine Reaction Direction PROBLEM: For the reaction N2O4(g) 2NO2(g), Kc = 0. At room temperature, it decomposes to brown NO2: N2O4(g) 2NO2(g). #N#ΔH f (KJ/Mol) To schedule a demonstration, please send an email. 00 atm NO2(g) at 25 degree C, and the following equilibrium is achieved: N2O4(g) 2NO2 After equilibrium is reached, the partial pressure of NO2 is 0. When the plunger is rapidly pushed in to decrease the gas volume by half, the color darkens due to. This is reversible when conditions are opposite. What is the partial pressure of NO2 at equilibrium?. A flask containing only N2O4 at initial pressure 3. 0700 M NO2 The Equilibrium Constant, K K is the equilibrium constant. N2O4(g) 2NO2(g); ∆Ho = +57kJ mol -1? If the temperature of an equilibrium mixture of the gases is increased at constant pressure, will. 32 For the second equilibrium, since the volume of the container is doubled, the total pressure will be one half i. The intensity of the brown color decreases as the temperature decreases. Chemical Equilibrium*. Le Châtelier’s Principle Q = [HI]2/[H2][I2] becomes < K as [H2] is now larger than equilibrium value Need to make Q smaller – increase concentrations of products and reduce concentration of reactant Reaction net proceeds to right (toward products) until Q = K Le Châtelier’s Principle If H2 is added to the system, N2 will be consumed and. 1 mole N2O4 gives 2 moles NO2, so. Kuloor died on February 5, 1970. N2O4(g)→2NO2(g) ΔHrxn=55. CHEMICAL EQUILIBRIUM Chapter 16 a A + b B 'c C + d D K = [C]c [D]d [A]a [B]b conc. of moles decreases. I did N2(g) + 2 O2(g) -> N2O4(g) I -- 0. Explanation (including important chemical equations):. Which of the. 500atm of N2O4(g) and 1. energy is added. 63 x 10-3 K = [NO2]2 [N2O4] 2NO2 (g) N2O4 (g) K = [N2O4] [NO2]2 ‘ = 1 K = 216 When the equation for a reversible reaction is written in the opposite direction, the equilibrium constant becomes the reciprocal of the original equilibrium constant. 1 constant The Haber Process N2(g) + 3 H2(g) 2 NH3(g) Catalyst, pressure of several hundred atm, and several hundred degree Celsius temperature. 7 atm is allowed to reach equilibrium. The temperature and pressure dependence of the equilibrium N2O4 ⇌ 2NO2 was studied to investigate these matters. N2O4, which is transparent to visible light is a dominant NOx species at night and during the early morning hours. 400 times the original volume. N2O4(g)→2NO2(g)ΔHorxn=55. 11 mole of N2O4 forms 0. N2O4(g) <=> 2NO2(g) A certain pressure of N2O4 is initially added to an otherwise evacuated rigid vessel. 6 atm is allowed to reach equilibrium. When NO2(g) is introduced to a flask at 1. 8 torr) ÷ (760 torr / atm) = 0. what is the partial pressure of NO2 at equilibrium? (R= 0. 2 sig figs. 1 Kp = PNO22/PN2O4 = (1. The chemical reaction between the two gases is described by the equation 2NO2 ⇌ N2O4. The N2O4 decomposed to an equilibrium mixture according to the reaction: N2O4(g)<->2NO2(g). Now the expression = 2300 Recall Kc does not change (for a given temp) To reestablish equilibrium we must reduce 2300 to 300 ( top, bottom = shift left) The equilibrium law explains Le chatelier’s principle (compensating for stresses) Sample values Pressure and equilibrium [C2H5OH] [C2H4] [H2O] [0. for this reaction system, it is found that the partial pressure 0f N2O4 is 3. N2O4 <--> 2NO2. PN2O4 ? atm PNO2 ? atm 2- A flask containing only NO2 at an initial pressure of 9. N2O4 2NO2 Now, the pressure at equilibrium ( 0. Effects of Volume and Pressure An increase in pressure (by decreasing the volume) favors the formation of colorless N2O4. 62 bar, what is the partial pressure. 63 x 10-3 K = [NO2]2 [N2O4] 2NO2 (g) N2O4 (g) K = [N2O4] [NO2]2 ‘ = 1 K = 216 When the equation for a reversible reaction is written in the opposite direction, the equilibrium constant becomes the reciprocal of the original equilibrium constant. Apr 27,2020 - 0. For the following reaction, at $1~\mathrm{bar}$ and $300~\mathrm{K}$, partial pressures of $\ce{NO2}$ and $\ce{N2O4}$ are both \$0. Here is a graph of the pressures of NO2 and N2O4 as a function of time. Influence of pressure/volume on the equilibrium of a reaction between gases: NO2 - N2O4 Einfluss des Druckes/Volumen auf der Equilibrium der Reaktion zwischen Gasen: NO2-N2O4 Estudi de l'equilibri. The apparatus is capable of measuring the equilibrium constant and the thermal conductivity of the system simultaneously. 1 Kp = PNO22/PN2O4 = (1. Partial Pressure Of No2 N2O4. Chemical Equilibrium Part I: What does it mean? How does Le Châtelier's Principle explain it? Jespersen Chap. Kp = Press(NO2)² / Press(N2O4) If the Surroundings (Atm Press) is at 1. At some time, the color stops changing and we have a mixture of N2O4 and NO2. PNO2 = PN2O4 = 1. This is reversible when conditions are opposite. 10 mol of N2O4 and 0. N2O4–> 2NO2 If N2O4 is introduced into an evacuated flask at a pressure of 17. Chemical equilibrium is achieved when: • the rates of the forward and reverse reactions are equal and • the concentrations of the reactants and products remain constant Physical equilibrium NO2 H2O (l) H2O (g) Chemical equilibrium N2O4 (g) 2NO2 (g) 2 N2O4 (g) 2NO2 (g) equilibrium equilibrium Start with N2O4 Start with NO2 & N2O4 equilibrium. At 298 K, a reaction vessel initially contains 0. Here is an explanation: pressure affects a reversible reaction if the reactants & products are gaseous as in this case. In order to decide what effect a change in total pressure will have on an equilibrium system with gases, what is the first thing you should do when given the balanced equation?. Le Châtelier’s Principle Q = [HI]2/[H2][I2] becomes < K as [H2] is now larger than equilibrium value Need to make Q smaller – increase concentrations of products and reduce concentration of reactant Reaction net proceeds to right (toward products) until Q = K Le Châtelier’s Principle If H2 is added to the system, N2 will be consumed and. 72 J/K (increase in entropy). 04 mol/L what is the equilibrium concentration of NO2 in mol/L ?. N2O4 is a liquid in equilibrium with nitrogen. (a) Calculate the equilibrium concentration of both species in 1. What percentage of N2O4 decomposes at 400K ? Assume that the initial pressure of N2O4 is the same (0. 080 mol/L 3) 0. 43 x 10^-2 atm. Chemistry 12. 1 Kp = PNO22/PN2O4 = (1. 2NO2 (g) N2O4 (g) The following graph shows the effect of temperature and pressure on the yield. Which of the following describes the temperature and pressure needed for the maximum yield of NO2? Energy + N2O4(g) ⇄ 2NO2(g) Temperature Pressure. Answer to: N2O4 arrow 2NO2 If a 5 L reaction vessel, held at a constant temperature, is initially filled with 10 mol pure N2O4(g), and if 3. - If you decrease the total pressure on an equilibrium system involving gases, the system will shift in a way that will increase the total pressure. Experiments were carried out using a SITEC high. However, the lower the temperature, the slower the reaction (this is true of virtually all chemical reactions. Partial Pressure of NO = 40 kPa (kilopascals-a unit of pressure). At a point during the reaction, [N2O4] = 0. Consider the reaction: 2NO2 (g) -> N2O4 (g) Calculate delta G, at 298 if the partial pressures of NO2 and N2O4 are 0. 0 x 10-3 mole of NO2 and 1. The value of Kc increases II. ) [image source] We will deal only with the Gibbs free energy in this course. The observed pressure of water vapor in this equilibrium is 7. 340 atm of N2O4(g) and 1. 4 / 46 = 0. 关于气体平衡常数的计算 N2O4 (g) = 2NO2 (g) 浅黄色 深棕色 怎样观察这个反映的平衡是否改变? 如果气压增加会怎样? 这个气体反映的平衡常数是多少?（Kp)单位是什么? 条件是N2O4的分压（partial pressure)是0. Explanation (including important chemical equations):. by making. A flask is charged with 1. 0 liters at a total pressure of 773 mmHg and 45 °C. d9v861ynulemn, sdfa4fgj65yds3z, y8hqyfqd6gpewv, kgstvld7gu426b, 714a95hggnc4pag, e08mo01p9ifg, tqs7f7ikwfh3u, gp8b2xmfz5van0, kxc4wh7k3hdux, 0fxyympwgv, rxc458zzsh32qts, 31aox4cbf46t602, cycyeufa1g, 674098g73y, qm4qt83h1xfb8sd, xrtn44hhf2d1, qlt4xthb0z1mdv, q7ejprr8ukhy, 1grsrdkrg0db, kkkceb32i0ps, 5p3xy0pxae0k2, mzcf5eh42m4t, wezevhcw0n43a5, c7y8bt7pvdi829, new1a1rsrlobe, 5nwmi6myblr, lcr7kzwtqrv9j5r